Learn to solve \u201cFind the City With the Smallest Number of Neighbors at a Threshold Distance\u201d using Floyd Warshall or a Dijkstra-per-source loop. Simple Python, step-by-step.<\/p>\n\n\n\n
Here’s the [Problem Link<\/span><\/mark><\/a><\/strong>] to begin with.<\/p>\n\n\n Given<\/p>\n\n\n\n compute for every city how many other cities can be reached with total travel distance \u2264 This is an all-pairs shortest-path (APSP)<\/strong> task followed by a simple count:<\/p>\n\n\n\n1. Problem recap<\/h2>\n\n\n\n
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n<\/code><\/strong> cities numbered 0 \u2026 n-1<\/code>,<\/li>\n\n\n\nedges = [u, v, w]<\/code>,<\/li>\n\n\n\ndistanceThreshold<\/code>.
Return the city that has the fewest such neighbors<\/strong>; if several tie, return the city with the largest index<\/strong>.<\/p>\n\n\n\n
\n\n\n\n2. Intuition<\/h2>\n\n\n\n